1 条题解
-
0
Pascal :
var m,n,i,j,k,max:longint; f,a:array[0..10,0..15]of longint; procedure print(i,j:longint); var k:longint; begin if i=0 then exit; for k:=0 to j do if max=f[i-1,k]+a[i,j-k] then begin max:=f[i-1,k]; print(i-1,k); writeln(i,' ',j-k); exit; end; end; begin readln(n,m); for i:=1 to n do for j:=1 to m do read(a[i,j]); for i:=1 to n do for j:=1 to m do begin max:=0; for k:=0 to j do if f[i-1,k]+a[i,j-k]>max then max:=f[i-1,k]+a[i,j-k]; f[i,j]:=max; end; writeln(f[n,m]); print(n,m); end.
- 1
信息
- ID
- 1159
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者