1 条题解

  • 0
    @ 2025-9-9 23:58:57

    C++ :

    #include <stdio.h>
    int main() {
        //FILE *fout;
    	//fout=fopen("output.txt","w");
    	double sum = 0;
    	double x;
    	int k;
     	for(x = 0.000; x <= 2.000; x += 0.001) {
    		sum = 0;
    		for(k= 1; k < 10000; k++) {
    			sum += (1.0 - x) / (k * (k + 1) * (k + x));
    		}
    		sum = sum + (1 - x) / (2 * 10000 * 10000) + 1.0;
    		//fprintf(fout,"%.3f %.12f\n", x, sum);
    		printf("%.3f %.12f\n", x, sum);
     	}
    	return 0;
    }
    
    
    • 1

    信息

    ID
    2353
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者