1 条题解

  • 0
    @ 2025-9-10 8:58:59

    C :

    #include<stdio.h>
    #include<math.h>
    const double Pi = 3.14;
    double Area( double Redius )
    {
    	double Are;
    	Are = Pi * pow( Redius, 2 );
    	return Are;
    }
    double Circumference( double Redius )
    {
    	double Cir;
    	Cir = 2 * Pi * Redius;
    	return Cir;
    }
    int main( int argc, char **argv )
    {
    	double Redius;
    	scanf( "%lf", &Redius );
    	double Are,Cir;
    	Are = Area( Redius ), Cir = Circumference( Redius );
    	printf( "周长=%.2f\n面积=%.2f\n", Cir, Are );
    	return 0;
    }
    

    C++ :

    //计算周长面积 
    #include <iostream>
    using namespace std;
    
    int main ()
    {
      float r, c, s;
      cin>>r;
    
      c = 3.14*r*2;
      s = 3.14*r*r;
    
    
      // 打印结果 
      cout <<"周长="<<c<<endl;
      cout <<"面积="<<s<<endl;
      // 结束程序 
      return 0;
    }
    

    Java :

    import java.math.BigDecimal;
    import java.util.Scanner;
    public class Main {
    	public static void main(String[] args) {
    		Scanner sc=new Scanner(System.in);
    		double r=sc.nextDouble();
    		double c=2*3.14*r;
    		double area=3.14*Math.pow(r, 2);
    		BigDecimal bg1=new BigDecimal(c);
    		BigDecimal bg2=new BigDecimal(area);
    		System.out.println("周长="+bg1.setScale(2, BigDecimal.ROUND_HALF_UP));
    		System.out.println("面积="+bg2.setScale(2, BigDecimal.ROUND_HALF_UP));
    	}
    }
    
    • 1

    信息

    ID
    3519
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    (无)
    递交数
    0
    已通过
    0
    上传者