1 条题解

  • 0
    @ 2025-9-10 9:00:39

    C :

    #include <stdio.h>
    
    main(){
       int n,i,sum;
       while (1 == scanf("%d",&n) && n) {
          sum = n;
          for (i=2;i*i <= n;i++) {
             if (n%i == 0) {
                sum -= sum/i;
             }
             while (n%i == 0) n /= i;
          }
          if (n > 1) sum -= sum/n;
          printf("%d\n",sum);
       }
    }
    
    

    C++ :

    #include <stdio.h>
    unsigned eulerFunc(unsigned n)
    {
    	unsigned ans = 1;
    	for (unsigned i = 2; i*i <= n; i++)
    	{
    		if (n % i == 0)
    		{
    			n /= i, ans *= (i-1);
    			while (n % i == 0) n /= i, ans *= i;//把质数除去,巧妙变相分解质因子
    		}
    	}
    	if (n > 1) ans *= (n-1);
    	return ans;
    }
    int main()
    {
    	int n;
    	while (scanf("%d", &n) && n !=0)
    	{
    		printf("%d\n", eulerFunc(n));
    	}
    	return 0;
    }
    
    • 1

    信息

    ID
    3601
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者